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4x^2-9x-48=0
a = 4; b = -9; c = -48;
Δ = b2-4ac
Δ = -92-4·4·(-48)
Δ = 849
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-\sqrt{849}}{2*4}=\frac{9-\sqrt{849}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+\sqrt{849}}{2*4}=\frac{9+\sqrt{849}}{8} $
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